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4.9t^2+2.21t-56.8=0
a = 4.9; b = 2.21; c = -56.8;
Δ = b2-4ac
Δ = 2.212-4·4.9·(-56.8)
Δ = 1118.1641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.21)-\sqrt{1118.1641}}{2*4.9}=\frac{-2.21-\sqrt{1118.1641}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.21)+\sqrt{1118.1641}}{2*4.9}=\frac{-2.21+\sqrt{1118.1641}}{9.8} $
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